Optimal. Leaf size=107 \[ -\frac{i d \text{PolyLog}\left (2,-e^{2 i (a+b x)}\right )}{2 b^2}+\frac{d \sin (a+b x) \cos (a+b x)}{b^2}+\frac{(c+d x) \log \left (1+e^{2 i (a+b x)}\right )}{b}+\frac{2 (c+d x) \sin ^2(a+b x)}{b}-\frac{d x}{b}-\frac{i (c+d x)^2}{2 d} \]
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Rubi [A] time = 0.180171, antiderivative size = 107, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 9, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.429, Rules used = {4431, 4404, 2635, 8, 4407, 3719, 2190, 2279, 2391} \[ -\frac{i d \text{PolyLog}\left (2,-e^{2 i (a+b x)}\right )}{2 b^2}+\frac{d \sin (a+b x) \cos (a+b x)}{b^2}+\frac{(c+d x) \log \left (1+e^{2 i (a+b x)}\right )}{b}+\frac{2 (c+d x) \sin ^2(a+b x)}{b}-\frac{d x}{b}-\frac{i (c+d x)^2}{2 d} \]
Antiderivative was successfully verified.
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Rule 4431
Rule 4404
Rule 2635
Rule 8
Rule 4407
Rule 3719
Rule 2190
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int (c+d x) \sec (a+b x) \sin (3 a+3 b x) \, dx &=\int \left (3 (c+d x) \cos (a+b x) \sin (a+b x)-(c+d x) \sin ^2(a+b x) \tan (a+b x)\right ) \, dx\\ &=3 \int (c+d x) \cos (a+b x) \sin (a+b x) \, dx-\int (c+d x) \sin ^2(a+b x) \tan (a+b x) \, dx\\ &=\frac{3 (c+d x) \sin ^2(a+b x)}{2 b}-\frac{(3 d) \int \sin ^2(a+b x) \, dx}{2 b}+\int (c+d x) \cos (a+b x) \sin (a+b x) \, dx-\int (c+d x) \tan (a+b x) \, dx\\ &=-\frac{i (c+d x)^2}{2 d}+\frac{3 d \cos (a+b x) \sin (a+b x)}{4 b^2}+\frac{2 (c+d x) \sin ^2(a+b x)}{b}+2 i \int \frac{e^{2 i (a+b x)} (c+d x)}{1+e^{2 i (a+b x)}} \, dx-\frac{d \int \sin ^2(a+b x) \, dx}{2 b}-\frac{(3 d) \int 1 \, dx}{4 b}\\ &=-\frac{3 d x}{4 b}-\frac{i (c+d x)^2}{2 d}+\frac{(c+d x) \log \left (1+e^{2 i (a+b x)}\right )}{b}+\frac{d \cos (a+b x) \sin (a+b x)}{b^2}+\frac{2 (c+d x) \sin ^2(a+b x)}{b}-\frac{d \int 1 \, dx}{4 b}-\frac{d \int \log \left (1+e^{2 i (a+b x)}\right ) \, dx}{b}\\ &=-\frac{d x}{b}-\frac{i (c+d x)^2}{2 d}+\frac{(c+d x) \log \left (1+e^{2 i (a+b x)}\right )}{b}+\frac{d \cos (a+b x) \sin (a+b x)}{b^2}+\frac{2 (c+d x) \sin ^2(a+b x)}{b}+\frac{(i d) \operatorname{Subst}\left (\int \frac{\log (1+x)}{x} \, dx,x,e^{2 i (a+b x)}\right )}{2 b^2}\\ &=-\frac{d x}{b}-\frac{i (c+d x)^2}{2 d}+\frac{(c+d x) \log \left (1+e^{2 i (a+b x)}\right )}{b}-\frac{i d \text{Li}_2\left (-e^{2 i (a+b x)}\right )}{2 b^2}+\frac{d \cos (a+b x) \sin (a+b x)}{b^2}+\frac{2 (c+d x) \sin ^2(a+b x)}{b}\\ \end{align*}
Mathematica [B] time = 5.82378, size = 254, normalized size = 2.37 \[ \frac{d \csc (a) \sec (a) \left (b^2 x^2 e^{-i \tan ^{-1}(\cot (a))}-\frac{\cot (a) \left (i \text{PolyLog}\left (2,e^{2 i \left (b x-\tan ^{-1}(\cot (a))\right )}\right )+i b x \left (-2 \tan ^{-1}(\cot (a))-\pi \right )-2 \left (b x-\tan ^{-1}(\cot (a))\right ) \log \left (1-e^{2 i \left (b x-\tan ^{-1}(\cot (a))\right )}\right )-2 \tan ^{-1}(\cot (a)) \log \left (\sin \left (b x-\tan ^{-1}(\cot (a))\right )\right )-\pi \log \left (1+e^{-2 i b x}\right )+\pi \log (\cos (b x))\right )}{\sqrt{\cot ^2(a)+1}}\right )}{2 b^2 \sqrt{\csc ^2(a) \left (\sin ^2(a)+\cos ^2(a)\right )}}-\frac{d \cos (2 b x) (2 b x \cos (2 a)-\sin (2 a))}{2 b^2}+\frac{d \sin (2 b x) (2 b x \sin (2 a)+\cos (2 a))}{2 b^2}+\frac{c \left (2 \sin ^2(a+b x)+\log (\cos (a+b x))\right )}{b}-\frac{1}{2} d x^2 \tan (a) \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.324, size = 177, normalized size = 1.7 \begin{align*} -{\frac{i}{2}}d{x}^{2}+icx-{\frac{ \left ( 2\,dxb+id+2\,bc \right ){{\rm e}^{2\,i \left ( bx+a \right ) }}}{4\,{b}^{2}}}-{\frac{ \left ( 2\,dxb-id+2\,bc \right ){{\rm e}^{-2\,i \left ( bx+a \right ) }}}{4\,{b}^{2}}}-2\,{\frac{c\ln \left ({{\rm e}^{i \left ( bx+a \right ) }} \right ) }{b}}+{\frac{c\ln \left ({{\rm e}^{2\,i \left ( bx+a \right ) }}+1 \right ) }{b}}-{\frac{2\,idax}{b}}-{\frac{id{a}^{2}}{{b}^{2}}}+{\frac{d\ln \left ({{\rm e}^{2\,i \left ( bx+a \right ) }}+1 \right ) x}{b}}-{\frac{{\frac{i}{2}}d{\it polylog} \left ( 2,-{{\rm e}^{2\,i \left ( bx+a \right ) }} \right ) }{{b}^{2}}}+2\,{\frac{ad\ln \left ({{\rm e}^{i \left ( bx+a \right ) }} \right ) }{{b}^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{c{\left (2 \, \cos \left (2 \, b x + 2 \, a\right ) - \log \left (\cos \left (2 \, b x\right )^{2} + 2 \, \cos \left (2 \, b x\right ) \cos \left (2 \, a\right ) + \cos \left (2 \, a\right )^{2} + \sin \left (2 \, b x\right )^{2} - 2 \, \sin \left (2 \, b x\right ) \sin \left (2 \, a\right ) + \sin \left (2 \, a\right )^{2}\right )\right )}}{2 \, b} - \frac{{\left (i \, b^{2} x^{2} - 2 i \, b x \arctan \left (\sin \left (2 \, b x + 2 \, a\right ), \cos \left (2 \, b x + 2 \, a\right ) + 1\right ) + 2 \, b x \cos \left (2 \, b x + 2 \, a\right ) - b x \log \left (\cos \left (2 \, b x + 2 \, a\right )^{2} + \sin \left (2 \, b x + 2 \, a\right )^{2} + 2 \, \cos \left (2 \, b x + 2 \, a\right ) + 1\right ) + i \,{\rm Li}_2\left (-e^{\left (2 i \, b x + 2 i \, a\right )}\right ) - \sin \left (2 \, b x + 2 \, a\right )\right )} d}{2 \, b^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 0.621951, size = 937, normalized size = 8.76 \begin{align*} \frac{2 \, b d x - 4 \,{\left (b d x + b c\right )} \cos \left (b x + a\right )^{2} + 2 \, d \cos \left (b x + a\right ) \sin \left (b x + a\right ) + i \, d{\rm Li}_2\left (i \, \cos \left (b x + a\right ) + \sin \left (b x + a\right )\right ) - i \, d{\rm Li}_2\left (i \, \cos \left (b x + a\right ) - \sin \left (b x + a\right )\right ) - i \, d{\rm Li}_2\left (-i \, \cos \left (b x + a\right ) + \sin \left (b x + a\right )\right ) + i \, d{\rm Li}_2\left (-i \, \cos \left (b x + a\right ) - \sin \left (b x + a\right )\right ) +{\left (b c - a d\right )} \log \left (\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right ) + i\right ) +{\left (b c - a d\right )} \log \left (\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right ) + i\right ) +{\left (b d x + a d\right )} \log \left (i \, \cos \left (b x + a\right ) + \sin \left (b x + a\right ) + 1\right ) +{\left (b d x + a d\right )} \log \left (i \, \cos \left (b x + a\right ) - \sin \left (b x + a\right ) + 1\right ) +{\left (b d x + a d\right )} \log \left (-i \, \cos \left (b x + a\right ) + \sin \left (b x + a\right ) + 1\right ) +{\left (b d x + a d\right )} \log \left (-i \, \cos \left (b x + a\right ) - \sin \left (b x + a\right ) + 1\right ) +{\left (b c - a d\right )} \log \left (-\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right ) + i\right ) +{\left (b c - a d\right )} \log \left (-\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right ) + i\right )}{2 \, b^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (d x + c\right )} \sec \left (b x + a\right ) \sin \left (3 \, b x + 3 \, a\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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